Question

Two trains travel for 11 hours, starting from the same place traveling in opposite directions. One train travels at an average rate that is 11 miles per hour faster than the other one. Find the rate of the slower train if they are 635 miles apart after FIVE hours.

Answer 1

58 mph

Explanation:

Let s represent the speed of the slower train. Then the distance apart is ...

distance = speed × time

s(5) +(s +11)(5) = 635

10s = 580 . . . . subtract 55

s = 58 . . . . . . . divide by 10

The slower train's rate is 58 miles per hour.