Question

1. A mountain climbing expedition establishes a base camp and two intermediate camps, A

and B. Camp A is 11,200 m east of and 3,200 m above base camp. Camp B is 8,400 m

east of and 1,700 m higher than Camp A. Determine the displacement between base camp

and Camp B.

Answer 1

Step-by-step explanation:

The diagram showing the illustration of the question is shown on the first uploaded image

Here G represents the base

So the displacement in the x -axis is mathematically represented as

`X = 11200 + 8400 = 19600 \ m`

The displacement in the y -axis is mathematically represented as

`Y 3200 + 1700 = 4900 \ m`

Generally the resultant displacement is

`R = √( X^2 + Y^2)`

`R = √( 19600^2 + 4900^2)`

`R = 20200\ m`

Generally the direction of this resultant displacement is mathematically represented as

`\theta = tan ^(-1) [(Y)/(X) ]`

=>
`\theta  =  tan ^(-1) [(4900)/(19600) ]`

=>
`\theta  = 14.03 ^o`

Hence the direction is [tex]14.03 ^o[\tex] from the horizontal axis