Question

What is the remainder when the sum of the smallest prime number and the second smallest prime number is divided by the third smallest prime number

Answer 1

Given:

The sum of the smallest prime number and the second smallest prime number is divided by the third smallest prime number.

To find:

The remainder.

Solution:

Prime numbers are the numbers which are divided by only 1 or itself.

Smallest prime number = 2

Second smallest prime number = 3

Third smallest prime number = 5

The sum of the smallest prime number and the second smallest prime number is divided by the third smallest prime number.

`(2+3)/(5)=(5)/(5)`

`(2+3)/(5)=1`

Since 5 is completely divided by 5, therefore, t he remainder is 0.