Question

Need help with calculus question

Answer 1

The value of the derivative at
`x=5` is the slope of the tangent line at the point
`(x,g(x))=(5,-4)`.

So the tangent line has equation

`y-g(5)=g'(5)(x-5)\implies y+4=6(x-5)\implies\boxed{y=6x-34}`