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If y=(x^2-4)^5(3x+4)^4

If y=(x^2-4)^5(3x+4)^4
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If y=(x^2-4)^5(3x+4)^4

If y=(x^2-4)^5(3x+4)^4-example-1
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User Bahadir
by
7.9k points

1 Answer

4 votes

Answer:


y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)

Explanation:


y=(x^2-4)^5(3x+4)^4


y'=[(d)/(dx)(x^2-4)^5](3x+4)^4+(x^2-4)^5[(d)/(dx)(3x+4)^4]


y'=10x(x^2-4)^4(3x+4)^4+(x^2-4)^5(12(3x+4)^3)


y'=10x(x^2-4)^4(3x+4)^4+12(x^2-4)^5(3x+4)^3


y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)

answered
User Pablo Lozano
by
8.0k points
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