Question

can someone help me, Just the answer don’t worry about explaining everything, Im really bad on Math :(

Answer 1

a. -2 b. -2 c. -1 d. 4 e. -3 f. 0

Explanation:

The average rate of change formula is:

`(y_(2)- y_(1))/(x_(2)-x_(1))`

a.

We need to find the rate of change for x = -3 to x = -2 so we look on the graph to find y.

At x = -3 it look like y = 0 so

`x_(1) = -3`

`y_(1) = 0`

At x = -2 it looks like y = 2

`x_(2) = -2`

`y_(2) = 2`

Now we can just plug everything in to the rate of change formula.

`(y_(2)- y_(1))/(x_(2)-x_(1)) = (2- 0)/(-3-(-2)) = (2- 0)/(-3+2) = (2)/(-1)` = -2

So for a. our rate of chage for the given interval is -2

b.

Now that you have the formula we don't need to explain each time.

`x_(1) =` -2

`y_(1) =` 2

`x_(2) =` 1

`y_(2) =` - 4

`(y_(2)- y_(1))/(x_(2)-x_(1)) = (-4- 2)/(1-(-2)) = (-4-2)/(1+2) = (-6)/(3)` = -2

c.

`x_(1) =` 0

`y_(1) =` -3

`x_(2) =` 1

`y_(2) =` - 4

`(y_(2)- y_(1))/(x_(2)-x_(1)) = (-4-(-3))/(1-0) = (-4 + 3)/(1-0) = (-1)/(1)` = -1

d.

`x_(1) =` 1

`y_(1) =` -4

`x_(2) =` 2

`y_(2) =` 0

`(y_(2)- y_(1))/(x_(2)-x_(1)) = (0 - (-4))/(2-1) = (0 + 4)/(2-1) = (4)/(1)` = 4

e.

`x_(1) =` -1

`y_(1) =` 0

`x_(2) =` 0

`y_(2) =` -3

`(y_(2)- y_(1))/(x_(2)-x_(1)) = (-3- 0)/(0-(-1)) = (-3- 0)/(0+1) = (-3)/(1)` = -3

f.

`x_(1) =` -1

`y_(1) =` 0

`x_(2) =` 2

`y_(2) =` 0

`(y_(2)- y_(1))/(x_(2)-x_(1)) = (0- 0)/(2-(-1)) = (0- 0)/(2+1) = (0)/(3)` = 0