Question

I need with the basic understanding of this​

Answer 1

A = air resistance

B = lift

C = thrust

D = gravity

1.00 N, 2.86° above horizontal

Step-by-step explanation:

Gravity pulls down on the bird. The thrust of the birds wings push it forward, and the lift pushes it up. Air resistance pushes it back.

The net force in the y direction is:

∑Fᵧ = lift − gravity

∑Fᵧ = 0.20 N − 0.15 N

∑Fᵧ = 0.05 N

The net force in the x direction is:

∑Fₓ = thrust − air resistance

∑Fₓ = 1.50 N − 0.50 N

∑Fₓ = 1.00 N

The magnitude of the resultant force is:

F² = Fₓ² + Fᵧ²

F² = (1.00 N)² + (0.05 N)²

F ≈ 1.00 N

The direction of the resultant force is:

tan θ = Fᵧ / Fₓ

tan θ = (0.05 N) / (1.00 N)

θ = 2.86° above horizontal