Question

Can anyone give me the answer for this and how to do it I’m lost

Answer 1

The answer the i got was -2(5y-27). The simplified answer is -10y+54.
You distribute 32 and -32 through the parentheses, reduce the fraction with 2. Collect like terms: 12y+24-32y+32+10y-2 = -10y+24+32-2. Collect the sum- and you get -10y+54

Answer 2

`\circ\sf\:32{\huge(}(3y)/(8)+(3)/(4){\huge)}-32(y-1)-32{\huge(}-(5y)/(16)+(2)/(32){\huge)}`

`\circ\sf\:{\huge(}((3* 32)y)/(8)+((3* 32))/(4){\huge)}-(32y-32)-{\huge(}-((5* 32)y)/(16)+((2* 32))/(32){\huge)}`

`\circ\sf\:[(3* 4)y+(3* 8)]-32y+32+(5* 2)y-2`

`\circ\sf\:12y+24-32y+32+10y-2`

`\circ\sf\:(12y-32y+10y)+(24+32-2)`

`\circ\sf\:54-10y`

`\circ\:\boxed{\bf{\purple{2(27-5y)} }}`