Calculate the pressure due to 500N force exerts on 0.02m {?}^(2) in contact area​

Question

Calculate the pressure due to 500N force exerts on


`0.02m {?}^(2)`
in contact area​

Answer 1

• Force = 500 N
• Area = 0.02 m^2
• We know, Pressure
• 
  `= (force)/(area)`
• Therefore, the pressure
• 
  `= (500)/(0.02) Pa \\ = (50000)/(2) Pa \\ = 25000Pa`

25000 Pa

Hope you could understand.

If you have any query, feel free to ask