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If p(x)=x^3-2x^2 + 0 x^6 - x + 1 coefficient of x^0 in p(x)

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7 votes

Answer:

1

Explanation:


p(x)=x^3-2x^2 + 0 x^6 - x + 1 \\ \\ \therefore \: p(x)=x^3-2x^2 + 0 x^6 - x + 1 {x}^(0) ( \because \: {x}^(0) = 1) \\ \\ \therefore \: coefficient \: of \: {x}^(0) = 1

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