asked 85.5k views
5 votes
How do you solve (5^{2} - 1) ÷ 6

asked
User Althia
by
8.7k points

2 Answers

4 votes

Answer:

4

Explanation:


\left(5^2-1\right)/ \:6\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(5^2-1\right)\::\quad 24\\=24/ \:6\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:24/ \:6\:\\:\quad 4

answered
User JPReddy
by
7.8k points
5 votes


( {5}^(2) - 1) / 6 =


(25 - 1) / 6 =


24 / 6 = 4

Note:

Do the square first, and then you do mathematic operation between the parentheses. And, then do the

mathematic operation in the outside of parentheses.

Thank you.

answered
User Jakube
by
7.8k points

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