Question

Parabola,,Could you help me please??

Answer 1

`\large \boxed{\sf \bf \sqrt{(10)/(3)}}`

Dimension of the rectangle is

`2*\sqrt{(10)/(3)}\\ \\10-(10)/(3)=(20)/(3)`

Explanation:

Hello,

`\text{The area is }2x(1-x^2) \\ \\\text{The derivative is }2(10-x^2)+2x(-2x)=2(10-3x^2)\\\\\text{The derivative is }0\text{ for} 10-3x^2=0 \\\text{so for } x=\sqrt{(10)/(3)}`

Thanks