Question

Write the equation of a line that is perpendicular to 6x - 3y - 15 = 0 and goes through the point (4, 6) in y-intercept form.

Answer 1

y= -1/2(x) +8

gradient= -1/2

Intercept= 8

Explanation:

Let's transform the equation to y -intercept form first

6x - 3y - 15= 0

-3y= -6x+15

Y= -6/-3(x) +(15/-3)

Y= 2x -5

Intercept c= -5

Gradient m =2

Rule of perpendicularity

mm'= -1

m'= -1/m

m' = -1/2

Equation of line of the point (4, 6)

(Y-Y1)/(x-x1)=m'

(Y-6)/(x-4)= -1/2

2(y-6)= -1(x-4)

2y -12 = -x +4

2y= -x +4+12

2y= -x+16

y= -1/2(x) +8

gradient= -1/2

Intercept= 8