Question

Find the distance between (5,-3) and (5,8).

Answer 1

Answer:
`11`

Explanation:

the distance between
`(5,-3)` and
`(5,8)` is
`11`, I know this because I Use the distance formula to determine the distance between two points.

the slope will be Undefined, and I know this because I use the slope formula to find the slope
`m`.

To find the mid-point, Use the midpoint formula to find the midpoint of the line segment.

`(5, (5)/(2) )`

From the Equation Using Two Points I will need to use the slope formula and slope-intercept form
`y=mx+b` to find the equation.

`x=5`

Answer 2

`\Longrightarrow: \boxed{\sf{11}}`

Explanation:

As with the slope formula, you must use the distance formula to determine the distance.

Use the slope formula.

Slope:

`\Longrightarrow: \sf{(y_2-y_1)/(x_2-x_1) }`

• y2=8
• y1=(-3)
• x2=5
• x1=5

Use the distance formula.

Distance formula:

`\Longrightarrow: \sf{√(\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2)}`

`\Longrightarrow: \sf{√(\left(5-5\right)^2+\left(8-\left(-3\right)\right)^2)}}`

Solve.

Use the order of operations.

PEMDAS stands for:

• Parentheses
• Exponents
• Multiply
• Divide
• Add
• Subtract

BODMAS stands for:

• Brackets
• Order
• Divide
• Multiply
• Add
• Subtract

`\sf{\left(5-5\right)^2+\left(8-\left(-3\right)\right)}`

First, do parentheses.

(5-5)²

5-5=0

`\sf{0^2+\left(8-\left(-3\right)\right)}`

(8-(-3))

=8+3

8+3=11

0²+11

Do exponents.

0²=0

0+11

Add.

0+11=11

`\Longrightarrow: \boxed{\sf{11}}`

• Therefore, the distance between (5,-3) and (5,8) is 11, which is our answer.