Answer:
16Km due east of school P
Explanation:
Given 
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same 
distance PQ = distance QP 
Thus, 
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q

as shown in figure P is west of Q,
now from point P , Q is west P.
Thus, 
Bearing of School Q from P is 16Km due east of school P