asked 42.0k views
0 votes
A 0.140-kg baseball is dropped and reaches a speed of 1.20 m/s just before it hits the ground. It rebounds with a speed of 1.00 m/s. What is the change of the ball's momentum

asked
User Nealmcb
by
8.4k points

1 Answer

2 votes

Final answer:

The change in momentum of the baseball, after it rebounds off the ground, is -0.308 kg.m/s, indicating a reversal in the direction of momentum.

Step-by-step explanation:

The question involves calculating the change in momentum of a baseball after bouncing off the ground. Momentum is defined as the product of an object's mass and velocity (p = m*velocity). When the baseball hits the ground and rebounds, there is a change in velocity, and hence a change in momentum.

Firstly, calculate the baseball's momentum just before impact: p before = 0.140 kg * 1.20 m/s = 0.168 kg.m/s. Then, calculate the momentum just after the rebound: p after = 0.140 kg * (-1.00 m/s) = -0.140 kg.m/s. The negative sign indicates the direction is opposite to the initial motion.

Next, find the change in momentum (∆p): ∆p = p after - p before = -0.140 kg.m/s - 0.168 kg.m/s = -0.308 kg.m/s. The change of momentum is a vector quantity, and in this context, the negative value indicates that the change is in the opposite direction of the initial momentum.

answered
User Neverpanic
by
8.2k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.