Question

How many grams of water is produced by the combustion of 32g of methane?

Answer 1

72g

Step-by-step explanation:

32 g of methane will produce =` 36/16 xx 32` = 72 g of water.

Answer 2

CH4 (g) + 2O2 (g) <=> CO2 (g) + 2H2O(g)

mole methane = 32 : 16 = 2

mole water (H2O) = 2/1 x 2 = 4 mole

mass water = 4 x 18 = 72 g