Question

A stone is thrown downward straightly its speed at speed of 20 second what and it reaches the ground at 40 metre second what will be the height of building

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Answer 1

`\Huge \boxed{\mathrm{61.22 \ m}}`

Explanation:

A stone is thrown downward straightly with the velocity of 20 m/s and it reaches the ground at the velocity of 40 m/s. What will be the height of building? (Question)

The initial velocity ⇒ 20 m/s

The final velocity ⇒ 40 m/s

We can apply a formula to solve for the height of the building.

`(V_f)2 - (V_i)^2 =2gh`

`V_f = \sf final \ velocity \ (m/s)`

`V_i = \sf initial \ velocity \ (m /s)`

`g = \sf acceleration \ due \ to \ gravity \ (m/s^2 )`

`h = \sf height \ (m)`

Plugging in the values.

Acceleration due to gravity is 9.8 m/s².

`(40)^2 - (20)^2 =2(9.8)h`

Solve for
`h`.

`1600 - 400 =19.6h`

`1200 =19.6h`

`\displaystyle h=(1200)/(19.6)`

`h= 61.22449`

The height of the building is 61.22 meters.