If a single circular loop of wire carries a current of 61 A and produces a magnetic field at its center with a magnitude of 1.70 10-4 T, determine the radius of the loop.

Question

asked Sep 15, 2021 82.0k views

1 Answer

Alfonse · Answer 1 · 2021-09-21T20:13:40+0000

Answer:

The radius is
$R = 0.22 5 \ m$

Step-by-step explanation:

From the question we are told that

The current is
$I = 61 \ A$

The magnetic field is
$B = 1.70 *10^(-4) \ T$

Generally the magnetic field produced by a current carrying conductor is mathematically represented as

$B = (\mu_o * I)/(2 * R )$

=>
$R = (\mu_o * I )/( 2 * B )$

Here
$\mu_o$ is the permeability of free space with value
$\mu_o = 4\pi * 10^(-7) N/A^2$

=>
$R = ( 4\pi * 10^(-7) * 61 )/( 2 * 1.70 *10^(-4) )$

=>
$R = 0.22 5 \ m$