Question

The length of a rectangle is 3 more than its width. If its perimeter is 54 m. Find its length & breadth and area and area.​

Answer 1

Width = 12 m

Length = 15 m

Area = 180 m²

Explanation:

Let, width = x

Length = x + 3

Perimeter = 54 m

Perimeter = 2 (l + w)

54 = 2 (x + 3 + x)

54/2 = 2x + 3

27 - 3 = 2x

24 = 2x

24/2 = x

12 m = x (width)

Length = x + 3 = 12 + 3 = 15 m

Area

= l × w

= 12 × 15

= 180 m²

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Hope it helps ⚜

Answer 2

Explanation:

Given:

• Length of the Rectangle is 3 more than its width.
• Perimeter of rectangle is 54 m

To Find:

• Length and Breadth
• Area of the rectangle

Solution:

We are given length of a rectangle is 3 more than its width

Let's assume:

• Breadth of the rectangle = x
• Length of the rectangle = x + 3

We know that,

`\dashrightarrow \sf \: \: Perimeter_((rectangle)) = 2(L + B)`

`\dashrightarrow \sf \: \: 54 = 2(x + x + 3)`

`\dashrightarrow \sf \: \: 54 = 2(2x + 3)`

`\dashrightarrow \sf \: \: (54)/(2) = 2x + 3`

`\dashrightarrow \sf \: \: 27 = 2x + 3`

`\dashrightarrow \sf \: \: 27 - 3 = 2x`

`\dashrightarrow \sf \: \: 24 = 2x`

`\dashrightarrow \sf \: \: (24)/(2) = x`

`\dashrightarrow \: \: {\underline{\boxed{\pink{\pmb{\mathfrak{12 = x}}}}}}`

Hence,

• Breadth of rectangle = x = 12 m
• Length of rectangle = 3 + x = 15 m

Now, Finding its area:

`\dashrightarrow \: \: { \sf{ Area_((rectangle)) = L * B }} \: \\`

`\dashrightarrow \sf \: \: Area = 12 * 15`

`\dashrightarrow \sf \: \: {\underline{\boxed{\pink{\pmb{\mathfrak{Area = 180 \: {m}^(2)}}}}}}`

Hence,

• Length and breadth of rectangle is 12 m and 15 m

• Area of the rectangle is 180 m²