Calculate the number of moles equivalent 10.0 gram of aluminium carbonate

Question

asked Dec 17, 2021 127k views

2 Answers

Maziyar Mk · Answer 1 · 2021-12-21T03:10:26+0000

$\LARGE{ \boxed{ \red{ \rm{Answer}}}}$

☃️ Chemical formulae ➝
$\sf{Al_2(CO_3)_3}$

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

$\boxed{ \sf{no. \: of \: moles = (given \: weight)/(molecular \: weight) }}$

❍ Molecular weight of
$\sf{Al_2(CO_3)_3}$

= 2 × 27 + 3 × 12 + 9 × 16

= 54 + 36 + 144

= 234

❍ Given weight: 10 g

Then, no. of moles,

⇛ No. of moles = 10 / 234

⇛ No. of moles = 0.0427 moles

⚘ No. of moles of Aluminium carbonate in the given weight = 0.0427 moles.

━━━━━━━━━━━━━━━━━━━━