Question

Solve logs (8 - 3x) = log20 for x.
A. X = 14
B. X = -13
C.x = -8
D. X= -4

Answer 1

`\boxed{\sf x = -4}`

Explanation:

`\sf Solve \: for \: x \: over \: the \: r eal \: numbers:`

`\sf \implies log(8 - 3x) = log 20`

`\sf Cancel \: logarithms \: by \: taking \: exp \: of \: both \: sides:`

`\sf \implies 8 - 3x = 20`

`\sf Subtract \: 8 \: from \: both \: sides:`

`\sf \implies 8 - 3x - 8 = 20 - 8`

`\sf \implies - 3x = 12`

`\sf Divide \: both \: sides \: by \: - 3:`

`\sf \implies (-3x)/(-3) = (12)/(-3)`

`\sf \implies x = - 4`

Answer 2

x = -4

Explanation:

logs (8 - 3x) = log20

Since we are taking the log on each side

log a = log b then a = b

8 -3x = 20

Subtract 8 from each side

8 -3x-8 =20 -8

-3x = 12

Divide by -3

-3x/-3 = 12/-3

x = -4