Question

A spray irrigation system waters a section of a farmer's field. If the water shoots a distance of 85 feet, what is the area that is watered as the sprinkler rotates through an angle of 60 degrees? Use 3.14 for pi . Round your answer to the nearest square foot, and enter the number only.

Answer 1

Answer:176

Explanation:

6 times 29.33333333333333

Answer 2

The watered area is approximately 3783 square feet.

Explanation:

The area that is watered due to the rotation of the spankler is a circular section area (
`A`), whose formula is:

`A = (\theta )/(2)* (1)/(360^(\circ))* 2\pi * d^(2)`

Where:

`d` - Water distance, measured in feet.

`\theta` - Rotation angle, measured in sexagesimal degrees.

Given that
`d = 85\,ft` and
`\theta = 60^(\circ)`, the watered area is:

`A = (60^(\circ))/(2) * (1)/(360^(\circ))* 2\pi * (85\,ft)^(2)`

`A \approx 3783\,ft^(2)`

The watered area is approximately 3783 square feet.