Question

Factorise using suitable identities (0.1x-0.2y)^2

Answer 1

Explanation:

(a - b)² = a² - 2ab + b²

a = 0.1x

b = 0.2y

(0.1x - 0.2y)²= (0.1x)² - 2*0.1x*0.2y + (0.2y)²

= (0.1)²x² - 0.04xy + (0.2)²y²

= 0.01x² - 0.04xy + 0.04y²