A wagon wheel consists of 8 spokes of uniform diameter, each of mass ms and length L cm. The outer ring has a mass mring. What is the moment of inertia of the wheel

Question

asked Sep 27, 2021 104k views

1 Answer

Speedogoo · Answer 1 · 2021-10-02T06:11:35+0000

Answer:

The moment of inertial of the wheel,
I = 8((1)/(3)M_sL^2 ) + M_rL^2

Step-by-step explanation:

Given;

8 spokes of uniform diameter

mass of each spoke, =
M_s

length of each spoke, = L

mass of outer ring, =
M_r

The moment of inertial of the wheel will be calculated as;

I = 8I_(spoke) + I_(ring)

where;

$I_{spoke$ is the moment of inertia of each spoke

$I_{ring$ is the moment of inertia of the rim

Moment of inertia of each spoke
=(1)/(3)M_sL^2

Moment of inertial of the wheel

I = 8((1)/(3)M_sL^2 ) + M_rL^2