Question

What is the internal energy of 3.00 mol of N2 gas at 25°C? To solve this

5
problem, use the equation: U diatomic gas
Remember that R = 8.31 J/(mol-K) and K = °C + 273.
= nRT
A.1560j
B.37,100j
C.623j
D.18,600j

Answer 1

E = 18,600 J

Step-by-step explanation:

It is given that,

Number of moles = 3

Temperature, T = 25°C = 25+273 = 298 K

The internal energy of N₂ gas is given by :

`U=f* nRT`

f is degrees of freedom. For diatomic gas, degree of freedom is equal to 5/2. So,

`U=(5)/(2)* 3* 8.31* 298\\\\U=18572.85\ J`

or

U = 18600 J

So, the internal energy of the gas is 18,600 J