Question

The Statue of Liberty weighs about 2.04 x 105 kg. The Washington Monument weighs about 9.07 x 107 kg. About how many more kilograms does the Washington Monument weigh than the Statue of Liberty?

Answer 1

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Explanation:

Answer 2

`9.05 * 10^(7) kg`

Explanation:

Given

`Statue\ of\ Liberty\ =\ 2.04 * 10^5 kg`

`Washington\ Monument\ =\ 9.07 * 10^7 kg`

To get the number of kilograms the Washington Monument weighs more than the Statue of Liberty, we simply calculate the difference;

Difference = Washington Monument - Statue of Liberty

`Difference = \ 9.07 * 10^7 kg - \ 2.04 * 10^5 kg`

Expand
`10^7`

`Difference = \ 9.07 * 10^(5+2) kg - \ 2.04 * 10^5 kg`

`Difference = \ 9.07 * 10^(5) * 10^2 kg - \ 2.04 * 10^5 kg`

Take out the common factor in the above expression

`Difference = 10^(5)\ (\ 9.07 * 10^2 kg - \ 2.04\ kg)`

`10^2 = 100;` so we have

`Difference = 10^(5)\ (\ 9.07 * 100 kg - \ 2.04\ kg)`

`Difference = 10^(5)\ (\ 907 kg - \ 2.04\ kg)`

`Difference = 10^(5)\ (904.96\ kg)`

Open bracket

`Difference =904.96 * 10^(5) kg`

Write in standard form

`Difference =9.0496 * 10^2 * 10^(5) kg`

`Difference =9.0496 * 10^7 kg`

`Difference =9.05 * 10^7 kg` (Approximated)

Hence, he Washington Monument weigh more than the Statue of Liberty by about
`9.05 * 10^(7) kg`