Question

what is an equation of the line that is perpendicular to y-4 = 2(x-6) and passes through the point (-3, -5)

Answer 1

y+5 = -1/2(x + 3)

Explanation:

Perpendicular lines have negative reciprocal slopes. The slope of the line

y - 4 = 2(x - 6) is 2. Its negative reciprocal slope is -1/2.

Using m = -1/2 and the point (-3,-5) in the point slope form.

y --5 = -1/2(x--3)

y+5 = -1/2(x + 3)

Answer 2

Explanation:

y - 4 = 2x - 12

y = 2x - 8

perp slope: -1/2

y + 5 = -1/2(x + 3)

y + 10/2= -1/2x - 3/2

y = -1/2x - 13/2