Question

Which answer needs to be true to be able to use the SSS Congruence Postulate to prove △ABC≅△DBC? AB¯¯¯¯¯¯¯¯≅DB¯¯¯¯¯¯¯¯ and ∠ACB≅∠DCB ∠ACB≅∠DCB and ∠A≅∠D AB¯¯¯¯¯¯¯¯≅DB¯¯¯¯¯¯¯¯ and AC¯¯¯¯¯¯¯¯≅DC¯¯¯¯¯¯¯¯ AB¯¯¯¯¯¯¯¯≅DB¯¯¯¯¯¯¯¯ or AC¯¯¯¯¯¯¯¯≅DC¯¯¯¯¯¯¯¯

Answer 1

AC≅DF

AB≅DE

Explanation:

took the test :)

Answer 2

The correct option is;

`\overline{AB}\cong \overline{DB}` and
`\overline{AC}\cong \overline{DC}`

Explanation:

The steps to prove that ΔABC ≅ ΔDBC with the SSS Congruence postulate

We have;

Statement, Reason

BC ≅ BC, Reflexive property

`\overline{AB}\cong \overline{DB}`, Option selected

`\overline{AC}\cong \overline{DC}`, Option selected

ΔABC ≅ ΔDBC, SSS Congruency Postulate

Therefore, whereby all three sides of the triangles ABC and DBC are congruent, then ΔABC is congruent to ΔDBC.