Question

For the following elementary reaction 2br• -> br2-. The rate of consumption of the reaction and the rate of formation of product is given by which set of expression? ​

Answer 1

Answer:
`-(1)/(2)* (d[Br^.])/(dt)=+(d[Br_2])/(dt)`

Step-by-step explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

`2Br^.\rightarrow Br_2`

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

`Rate=-(d[Br^.])/(2dt)`

or
`Rate=+(d[Br_2])/(dt)`

Thus
`-(d[Br^.])/(2dt)=+(d[Br_2])/(dt)`