Question

When 10 b = 5 (StartRoot c EndRoot + 2) is solved for c, one equation is c = (2b minus 2) squared Which of the following is an equivalent equation to find c? c = 10 b minus 10 minus 5 c = (10 b minus 10 minus 5) squared c = StartFraction (10 b minus 2) squared Over 25 EndFraction c = StartFraction (10b minus 10) squared Over 25 EndFraction

Answer 1

d on edgenuity

Explanation:

Answer 2

Option D.

Explanation:

The given equation is

`10b=5(√(c)+2)`

We need to find an equation which is equivalent to the given equation.

Using distributive property, we get

`10b=5(√(c))+5(2)`

`10b=5√(c)+10`

Subtract both sides by 10.

`10b-10=5√(c)`

Divide both sides by 5.

`(10b-10)/(5)=√(c)`

Taking square on both sides.

`\left((10b-10)/(5)\right)=(√(c))^2`

`((10b-10)^2)/(25)=c`

`c=((10b-10)^2)/(25)`

This equation is equivalent to the given equation.

Therefore, the correct option is D.