Question

What is the specific heat of a 85.01 g piece of an unknown metal that exhibits a 45.2°C temperature change upon absorbing 1870 J of heat?

Answer 1

`0.48~(J)/(g~^(\circ)C)`

Step-by-step explanation:

In this question, we have to remember the relationship between Q (heat) and the specific heat (Cp) the change in temperature (ΔT), and the mass (m).

`Q=m*Cp*ΔT`

The next step is to identify what values we have:

`Q~=~1870~J`

`m~=~85.01~g`

`ΔT~=~45.2~^(\circ)C`

`Cp~=~X`

Now, we can plug the values and solve for "Cp":

`1870~J=~85.01~g~*Cp*45.2~^(\circ)C`

`Cp=(1870~J)/(85.01~g~*45.2~^(\circ)C)`

`Cp=0.48~(J)/(g~^(\circ)C)`

The unknow metal it has a specific value of
`0.48~(J)/(g~^(\circ)C)`

I hope it helps!