Question

What volume of hydrogen iodide is produced when 118 liters of hydrogen gas react according to the following reaction? (All gases are at the same temperature and pressure.) hydrogen(g) + iodine(s) hydrogen iodide(g) liters hydrogen iodide

Answer 1

`V_(HI)=236LHI`

Step-by-step explanation:

Hello,

In this case, for the given balanced chemical reaction:

`H_2(g)+I_2(g)\rightarrow 2HI(g)`

Thus, since hydrogen and hydrogen iodide are in a 1:2 mole ratio, we can easily compute the yielded volume as shown below:

`V_(HI)=118LH_2*(2molHI)/(1molH_2) \\\\V_(HI)=236LHI`

Thus, is possible, due to the Avogadro's law which allows to relate moles and volume by a directly proportional relationship.

Regards.