Question

Find the sum. Please

Answer 1

`(2y^2 +12y -8)/(y^3-3y+2)`

Explanation:

It usually works to factor the denominators, so you can determine the least common denominator.

`(2y)/(y^2-2y+1)+(8)/(y^2+y-2)=(2y)/((y-1)^2)+(8)/((y-1)(y+2))\\\\=(2y(y+2))/((y-1)^2(y+2))+(8(y-1))/((y-1)^2(y+2))=(2y^2+4y+8y-8)/((y-1)^2(y+2))\\\\=\boxed{(2y^2 +12y -8)/(y^3-3y+2)}`