Question

What are the center and radius of the circle defined by the equation x2 + y2 - 6x + 4y + 4 = 0 A. Center (3, -2); radius 9 B. Center (-3, 2) radius 9 C. Center (3, -2); radius 3 D. Center (-3, 2); radius 3

Answer 1

Answer: answer above is correct I just did my final

Explanation:

Answer 2

C. Center: (3, -2); radius: 3

Explanation:

x^2 + y^2 - 6x + 4y + 4 = 0

We need to complete the square in x and y.

x^2 - 6x + y^2 + 4y = -4

x^2 - 6x + 9 + y^2 + 4y + 4 = -4 + 9 + 4

(x - 3)^2 + (y + 2)^2 = 9

Center: (3, -2); radius: 3