If 0.360 J of heat is added to 0.7402 g of water, how much will the temperature increase?

Question

asked Oct 26, 2021 167k views

2 Answers

Leonardo Scotti · Answer 1 · 2021-11-01T03:34:47+0000

Answer:

ΔT = 0.116 °C

Step-by-step explanation:

Using Formula

Q = mc ΔT

Where Q = 0.360, c = 4.184 and m = 0.7402

ΔT = Q/mc

ΔT = 0.360/ (4.184)(0.7402)

ΔT = 0.360 / 3.097

ΔT = 0.116 °C

So, The change in Temperature/Increase in Temperature is 0.116 °C