asked 203k views
3 votes
Find the x-intercepts for the parabola defined by this equation

Find the x-intercepts for the parabola defined by this equation-example-1

2 Answers

1 vote

Answer:

The coordinates are (5 ,0) and (1 ,0)

Answer is given below with explanations.

Explanation:


to \: find \: the \: x \: intercepts \: of \: the \: parabola \: \\ defined \: by \: {x}^(2) - 6x + 5 = y \\ let \: y = 0 \\ then \\ {x}^(2) - 6x + 5 =0 \\ by \: factorization \\ (x - 5)(x - 1) = 0 \\ x - 5 = 0 \: \: (or )\: x - 1 = 0 \\ x = 5 \: \: ( or) \: x = 1

We want ti express the intercepts as two ordered pairs (y = 0)

Then the coordinates are (5 ,0) and (1 ,0)

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION.

answered
User Seetha
by
8.3k points
5 votes

Answer:

Your x-intercepts are (1, 0) and (5, 0)

Explanation:

Factor out the expression:


y =x^(2) -6x +5 factors out to
y = (x-1) * (x-5)

Because this factored out form is now in intercept form, we can solve that the two intercepts are (1, 0) and (5, 0).

answered
User Aorlinn
by
7.7k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.