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2 votes
In a lottery daily game, a player picks three numbers from 0 to 9 (without repetition). How many different choices does the player have if order does not matter

2 Answers

0 votes

Final answer:

The player has 120 different choices in the lottery daily game when order does not matter.

Step-by-step explanation:

To find the number of different choices the player has, we can use the concept of combinations.

Since order does not matter, we can use the formula for combinations to calculate the number of choices.

The formula for combinations is:

C(n, r) = n! / (r!(n-r)!)

Where n is the total number of options and r is the number of options selected.

In this case, n = 10 (from 0 to 9) and r = 3 (the player picks three numbers).

Plugging in the values, we get:

C(10, 3) = 10! / (3!(10-3)!) = 10! / (3!7!)

Simplifying, we get:

C(10, 3) = (10 × 9 × 8) / (3 × 2 × 1) = 120

Therefore, the player has 120 different choices.

answered
User Kushtrim
by
7.8k points
3 votes

Answer:

Not sure 3/10?

Step-by-step explanation:

numbers are 0-9...that's 10 choices.

he chooses 3 numbers

I would think 3/10?

answered
User Xupitan
by
8.2k points

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