To the nearest tenth, which is the perimeter of ABC. Geometry

Question

asked Oct 15, 2021 23.4k views

2 Answers

Godbyk · Answer 1 · 2021-10-22T01:36:56+0000

Answer:

23.6

Explanation:

Finding AC:

Cos 61 =
(adjacent)/(hypotenuse)

0.48 × 10 = Adjacent

AC = 4.8

Now, CB:

Cos 29 =
(adjacent)/(hypotenuse)

0.87 × 10 = CB

CB = 8.8

The perimeter:

=> 10+4.8+8.8

=> 23.6