Question

During batting practice, two pop flies are hit from the same location, 2 s apart. The paths are modeled by the equations h = -16t^2 + 56t and h = -16t^2 + 156t - 248, where t is the time that has passed since the first ball was hit. Explain how to find the height at which the balls meet. Then find the height to the nearest tenth.

Answer 1

40.5 is the answer therefore The balls meet at a height of ⇒ 40.5 ft.

Explanation:

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Answer 2

2.5 seconds since the first ball was hit.

Explanation:

The equations that model the heights are:

• h = -16t² + 56t

• h = -16t² + 156t - 248

When the balls meet, both heights are equal, therefore:

-16t² + 56t = -16t² + 156t - 248

-16t² + 56t + 16t² - 156t + 248 = 0

- 100t + 248 = 0

248 = 100t

248/100 = t

t = 2.48 ≈ 2.5