Question

If 0.5 L of a gas is cooled from 22°C to 4°C, what is the new volume of the gas?

ОА
0.02 L
B
0.47 L
С
0.60 L
D
2.75 L

Answer 1

B

Step-by-step explanation:

From charles' law,

`v \alpha t`

where v is volume and t is absolute temperature

• 
  `(v1)/(t1) = (v2)/(t2)`
• 
  `v1 = 0.5l \\ t1 = (22 + 273 )k\\ t2 = (4 + 273)k \\ t1 = 295k \\ t2 = 277k \\ (0.5)/(295) = (v2)/(277) \\ v2 = 277 * (0.5)/(295) = 0.47l`
• Hence that's it