Question

Help please! This is a Calculus AB question!

Answer 1

½ ln 3

Explanation:

∫ sec²x / tan x dx

If u = tan x, then du = sec²x dx.

∫ du / u

ln|u| + C

ln|tan x| + C

Evaluate between π/4 and π/3.

ln|tan(π/3)| + C − (ln|tan(π/4)| + C)

ln|√3| + C − ln|1| − C

ln(√3)

½ ln 3