asked 168k views
4 votes
You randomly select one card from a 52-card deck. Find the probability of selecting the four of spades or the ace of clubs.

(Type answer an integer or a fraction. Simplify your answer.)

asked
User Stsloth
by
8.0k points

2 Answers

3 votes

Answer:

P(four of spades or ace of clubs)= 1/26

Explanation:

In a deck of 52 cards, there is one four of spaces and one ace of clubs. we want to find the probability of selecting those cards.

P(four of spades or ace of clubs)=four of spades+ace of clubs/total cards

There is 1 four of spades and 1 ace of clubs. 1+1=2

P(four of spades or ace of clubs)=2/total cards

There are 52 total cards in a deck.

P(four of spades or ace of clubs)=2/52

This fraction can be simplified. Both the numerator (top number) and denominator (bottom number) can be divided by 2.

P(four of spades or ace of clubs)= (2/2) / (52/2)

P(four of spades or ace of clubs)= 1/26

answered
User Rus Paul
by
8.0k points
5 votes

Answer:

1/26

Explanation:

There is 1 four of spades, and 1 ace of clubs.

So the probability is 2/52, or 1/26.

answered
User Tapas Mukherjee
by
8.6k points
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