Question

An 8-sided fair die is rolled twice and the product of the two numbers obtained when the die is rolled two times is calculated.

(A) Draw the possibility diagram of the product of the two numbers appearing on the die in each throw

Answer 1

The answer is "64".

Explanation:

Given:

8-sided fair die

output of Die = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 }

if the Dice is thrown two times. so, the possible outputs are as follows:

`\to 8 * 8=64`

`\texttt{ = (1,1),(1,2),(1,3),(1,4),(1,5),(1,6),}\\ \ \ \texttt{(1,7),( 1, 8),(2,1),(2,2),(2,3),(2,4),}`

`\texttt{(2,5),(2,6),(2,7),(2,8),(3,1), (3,2),}\\ \texttt{(3,3),(3,4),(3,5),(3,6),(3,7),(3,8) ,}\\\texttt{(4,1),(4,2),(4,3), (4,4),(4,5),(4,6),} \\`

`\texttt{(4,6),(4,7),(4,8),(5,1),(5,2),(5,3),}\\\texttt{(5,4),(5,5),(5,6),(5,7),(5,8),(6,1),}\\\texttt{(6,2),(6,3),(6,4),(6,5),(6,6),(6,7),}`

`\texttt{(6,8),(7,1),(7,2),(7,3),(7,4),(7,5),} \\\texttt{(7,6),(7,7),(7,8),(8,1),(8,2),(8,3),}\\ \texttt{(8,4),(8,5),(8,6),(8,7),(8,8)}`

That's why the product is 64.