Question

What is the total pressure of air in lungs of an individual with oxygen at 100. mmHg, nitrogen at 573 mmHg, carbon dioxide at 0.053 atm, and water vapor at 47 torr?

Answer 1

Answer: The total pressure of air in lungs of an individual is 760.28 mm Hg

Step-by-step explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

`p_(total)=p_A+p_B+p_C...`

Given :
`p_(total)` =total pressure of gases = ?

`p_(O_2)` = partial pressure of oxygen = 100 mm Hg

`p_(N_2)` = partial pressure of nitrogen = 573 mm Hg

`p_(CO_2)` = partial pressure of Carbon dioxide = 0.053 atm = 40.28 mm Hg(1 atm = 760 mmHg)

`p_(H_2O)` = partial pressure of water vapor = 47 torr = 47 mm Hg (1torr=1 mm Hg)

putting in the values we get:

`p_(total)=(100+573+40.28+47)mmHg`

`p_(total)=760.28mmHg`

Thus the total pressure of air in lungs of an individual is 760.28 mm Hg