Question

Find The equation of a circle that has it center at (-4,3) and has a radius of 5.

Answer 1

`{(x - h)}^(2) + {(y - k)}^(2) = {r}^(2) \\ </p><p></p><p> {(x - (4))}^(2) + {(y + 3))}^(3) = {5}^(2) \\ {(x - 4)}^(2) + {(y + 3)}^(2) = 25`

Answer 2

A.

Explanation:

Center = (a,b) = (-4,3)

So, a = -4, b = 3

Radius = 5

Equation of circle:

`(x-a)^2+(y-b)^2 = r^2`

Putting the givens

=> (x+4)²+(y-3)² = 25