Question

What volume of 10,0 M H2SO4 is required to prepare 4.0 L of 0.50 M H2SO4?

A) 0.20 L
B) 0.40 L
C) 0.50 L
D) 1.0L
E) 4.0L

Answer 1

Answer: A) 0.20 L

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

According to the neutralization law,

`M_1V_1=M_2V_2`

where,

`M_1` = molarity of stock
`H_2SO_4` solution = 10.0 M

`V_1` = volume of stock
`H_2SO_4` solution = ?

`M_2` = molarity of dilute
`H_2SO_4` solution = 0.50 M

`V_2` = volume of dilute
`H_2SO_4` solution = 4.0 L

`10.0* V_1=0.50* 4.0`

`V_1=0.20L`

Therefore, the volume of 10.0 M
`H_2SO_4` solution needed to prepare 4.0 L of 0.50 M
`H_2SO_4` is 0.20 L