asked 68.1k views
3 votes
What is the equation of the circle that is centred at the origin and passes through the point (-3,4)

asked
User Gillie
by
8.3k points

1 Answer

4 votes

Answer:

The correct answer is (x)² + (y)² = r².

Explanation:

The standard equation for a circle is (x - h)² + (y - k)² = r². Since our circle is centered at the origin, or (0, 0), our values for h and k are simply 0 and 0, so there is no need to list these values within the equation.

Now, it is time to determine r, or the radius of the circle. The circle passes through the point (-3, 4), so (-3)² + (4)² = 25², so r = 25.

Therefore, your equation is x² + y² = 25.

answered
User Leon Latsch
by
8.9k points
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