Question

At STP, what is the volume in milliliters of 0.0395 mol of fluorine gas, F2?

Answer 1

884.8 mL

Step-by-step explanation:

If we have STP condition (Standard temperature and pressure), we will have the following relationship:

`1~mol=22.4~L` or
`1~mol=22400~mL`. With this in mind we can do the conversion:

`0.0395~mol(22400~mL)/(1~mol)=884.8~mL`

In the 0.0395 mol of fluorine gas, we will have 884.8 mL of gas at STP conditions.