Question

Find all the real zeros
f(x)=-2x^2-6x-1​

Answer 1

Explanation:

real zeros -----> where f(x) = 0

`-2x^(2) - 6x - 1 = 0\\` * (-1)

`2x^(2) + 6x + 1 = 0\\`

Δ =
`6^(2) - 4 * 2 * 1` = 36 - 8 = 28

vΔ = 2
`√(7)`

x' =
`(-6 + 2√(7) )/(2 * 2) = \frac{-6 +2√(7) }4}`

x'' =
`(-6 - 2√(7) )/(2 * 2) = \frac{-6 -2√(7) }4}`